I am using gulp-uglify with my gulp setup to mimify my js code for production environment.
I have code like this
var test = 1;
function getTest(myTest)
{
if(!myTest) {
return test;
}
return myTest;
}
However when I run gulp the output becomes (I kept it clean for readability)
function getTest(myTest)
{
if(!myTest) {
return test;
}
return myTest;
}
var test = 1;
How can I prevent gulp-uglify
from changing the order or my global variables.
I first concatenate my files, then uglify.
I try to pass the following object to uglify
but it is still shifting the order.
uglify({ mangle: false })
uglify({ mangle: { reserved: ['test'] } })
Here is a list of the dependencies
"license": "ISC",
"devDependencies": {
"gulp": "^3.9.1",
"gulp-autoprefixer": "^3.1.1",
"gulp-concat": "^2.6.0",
"gulp-debug": "^2.1.2",
"gulp-ignore": "^2.0.1",
"gulp-minify-css": "^1.2.4",
"gulp-sass": "^2.3.2",
"gulp-sourcemaps": "^1.6.0",
"gulp-uglify": "^2.0.0",
"gulp-util": "^3.0.7"
}
here is my gulp task
gulp.task('compileJs', function () {
gulp.src(jsFiles['final'])
.pipe(sourcemaps.init())
//only uglify if gulp is ran with '--type production'
.pipe(isProduction() ? uglify() : gutil.noop())
.pipe(concat('final.js'))
.pipe(sourcemaps.write())
.pipe(gulp.dest('./Public/Js'));
});
via Mike A
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