From a function, how to get details about the module which actually called this function?

In a general-purpose function, I would like to get informations about the module which calls this function (especially the base directory, which can itself be retrieved inside a module with path.dirname(module.filename)).

What I tried

For now, the only way I found to do it is to add module as a parameter for the function:

lib/my-lib.js:

const path = require('path');

exports.print_calling_module_path = function(calling_module) {
    console.log(path.dirname(calling_module.filename));
}

main.js:

const my_lib = require('./lib/my-lib.js');

console.log('Here is the path of this actual module:');
my_lib.print_calling_module_path(module);

... but it forces to use an extra parameter, which pollutes the argument list of functions with a (possibly?) deductible information.

What I'm looking for

For example:

lib/my-lib.js:

const path = require('path');

exports.print_calling_module_path = function(/* no extra argument */) {
    let calling_module = .... ;  // <== How to get this ??
    console.log(path.dirname(calling_module.filename));
}

main.js:

const my_lib = require('./lib/my-lib.js');

console.log('Here is the path of this actual module:');    
my_lib.print_calling_module_path(/* no extra argument */);

Inside the print_calling_module_path() function, how can I deduct the calling module's whole path without passing it as a parameter? Maybe something dealing with the stack trace?

via yolenoyer