Create mapping to a literal query in sequelize

I have a custom attribute in my sequelize query and it returns correctly, but I cannot figure out how to map it to the object.

The broad idea is to get all users with their relationship to the logged user.

The query goes like this:

db.user.findAll({
include: [
  {model: db.friend, as: 'from_user', required: false, where:{ to_user_id: logged_user_id }  },
  {model: db.friend, as: 'to_user', required: false, where:{ from_user_id: logged_user_id }  },
 ],
attributes: { include: [[
  db.sequelize.literal(
    `CASE 
        WHEN 'to_user.status' = 'accepted' OR 'from_user.status' = 'accepted' THEN 'friend'
        WHEN 'to_user.status' = 'new' THEN 'i_invited'
        WHEN 'from_user.status' = 'new' THEN 'he_invited'
        ELSE 'stranger' 
     END`
  ),
   'relationship'
 ]]},

The attribute that is returned, but not mapped is of course relationship.

const user = sequelize.define<IUserInstance, IUserAttributes>('user', {
id: {
  type: dataTypes.STRING,
  allowNull: false,
  unique: true,
  defaultValue: () => generate(),
},
//some other fields...
}, {
classMethods: {
  associate: (models) => {
    user.hasOne(models.friend, {
      foreignKey: 'from_user_id',
      constraints: false,
      as: 'from_user',
    });
    user.hasOne(models.friend, {
      foreignKey: 'to_user_id',
      constraints: false,
      as: 'to_user',
    });
  }
},
timestamps: true,
paranoid: true,
underscored: true,
});

Of course IUserInstance and IUserAttributes have a relationship defined in them.

How do I ensure that the relationship is mapped to IUserAttributes?

via Michał K